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| Sukasa Posts: 786/2068 |
THANK YOU VERY MUCH.
That will help me very much both in programming and in making up a better file with definitions of the different styles of addressing and that for 65816. |
| MathOnNapkins Posts: 391/1106 |
The brackets indicated a long pointer, i.e. 24 bit and hence 3 bytes. The address inside the brackets is a direct page address.
So for example if you do LDA [$00] and at $7E:0000 there are the values 00 80 7F, the value loaded into A will be the value at $7F:8000. How many bytes are stored of course depends on the M register. You can also use the Y register as an index, and do LDA [$00], Y. That will load the value at $7F  8000 + Y). I've heard that even works across bank boundaries but don't quote me on that. Read it in one of Nach's documents.
LDA ($00) by contrast, does something similar but uses the Databank register's current value and hence only needs to fetch 2 bytes to form an address. |
| Sukasa Posts: 784/2068 |
In 65816, ther is a command that goes somewhat like LDA [&xx]. Am I right in assuming that from what I understand of the command, that the processor would load A with the value in RAM that $xx points to, e.x. if $xx is $02, and at $02 there is the value #$04, then A would be loaded with #$04 after LDA [$xx]?
If so, how many bytes large is the address pointer that would be stored in $xx? 1, 2, or 3 bytes large? |
