Register | Login | |||||
Main
| Memberlist
| Active users
| Calendar
| Chat
| Online users Ranks | FAQ | ACS | Stats | Color Chart | Search | Photo album |
| |
0 users currently in General Chat. |
User | Post | ||||||
spel werdz rite Posts: 191/1796 |
Originally posted by ZemA block of gold will do.Originally posted by spel werdz riteOriginally posted by Mari0megaI'm in 10th grade, and I discussed this with math teachers when I was in eighth grade. Make it 1/0 pounds. | ||||||
Zem Posts: 163/1097 |
Originally posted by spel werdz riteOriginally posted by Mari0megaI'm in 10th grade, and I discussed this with math teachers when I was in eighth grade. What do you want, a prize? | ||||||
spel werdz rite Posts: 172/1796 |
Originally posted by Mari0megaI'm in 10th grade, and I discussed this with math teachers when I was in eighth grade. | ||||||
jordan_mega_gamer Posts: 24/41 |
Okay, this is getting far too complex for a 10th grader like myself, but I'll try to contribute anyway. You really don't need the math for this situation, because it's kind of common sense.
Let me take the classic cookie example. Say you're dividing a cookie amongst people. How much of a cookie will each person get? What happens if we divide a cookie amongst 0 people? The common sense answer is, "Who cares?" The whole point of division is to divide something into X equal parts. If you're dividing by 0, you're pretty much saying, "Okay, we have one cookie divided into 0 pieces. How big is each piece?" It doesn't work, but it doesn't need to work. On the other hand, let's say you're dividing a cookie into an infinite number of pieces. How big is each piece? Well, usless you plan of splitting an atom, and thus destroying the cookie entirely, there'll always be a little left. You can't cut something into such tiny pieces that it vanishes. Again, it doesn't work, but doesn't really need to. I agree with Squash Monster: it's best viewed as a limit. Of course, maybe something like this is somewhat useful in more advanced math. This is from a 10th-grader's point of view. And IMO, there just can't be multiple infinities. The definition of infinity is the biggest possible number. Thus, if there's a bigger infinity, it'd become the new and only infinity. | ||||||
Crystal Shards Posts: 5/7 |
Way too long, and no, I've got a steady job, and an appartment. Thanks though. | ||||||
spel werdz rite Posts: 162/1796 |
Originally posted by Crystal ShardsObsessions are what allow things to be great. | ||||||
MathOnNapkins Posts: 98/1106 |
Wow, Shards is back. How long were you away? Are you still homeless? | ||||||
Crystal Shards Posts: 3/7 |
Wow. You guys are getting WAY too into this.
The premise behind his equation (though not necessarily the ones expressed by the users here), lies in this statement: "In other words, Z is a "number", so unlogically big that when it's multiplied by 0, it becomes 1." I stopped reading after that, as there was no point. Regardless of how illogically big the number is- it could encompass twice the space of the universe with it's hugeness- if you have zero quanity of that number, then you have nothing, typically expressed by the word zero. Anything whatsoever x 0 = 0. Always. | ||||||
spel werdz rite Posts: 158/1796 |
Lets look at this:
1/1=1 1/0.5=2 1/0.25=4 1/0.125=8 You guys are assuming that the smaller the denominator gets, the larger the number will be. Lets say you go low enough to 1/0.0000000001=1,000,000,000 You're saying that after it decreases more (now we'll say zero), it would be that largest number possible, even infinite. 1/0=Infinity But what happens if it were to still decrease? Will it get even higher? 1/-0.0000000001=-1,000,000,000 1/-0.125=-8 1/-0.25=-4 1/-0.5=-2 1/-1=-1 1/0 doesn't work because it's the cross between extremely large and extremely small. Here's another example: 1/10=0.1 1/100=0.01 1/1,000=0.001 1/10,000=0.0001 This time, the larger the denominator, the smaller the number. If it were one divided by an extremely large number (infinity) it would be zero. But look at its oppposite. 1/-10=-0.1 1/-100=-0.01 1/-1,000=-0.001 1/-10,000=-0.0001 The smaller the denominator, the larger the number. If this time it were one over an extremely small number (-infinity) it would once again be zero. Look at the graph y=1/x. The asymptopes of the graph display were the function does not work. If anyone has a basic Algebra II education, they would know this. We've had professional mathematicians for the last 5,000 years, we know what were talking about. | ||||||
MathOnNapkins Posts: 93/1106 |
If you view it in the complex plane, all infinities are the same, so you don't need a + or -. It's just a complex number with arbitrarily large modulus (radius).
It's nice to muse about what 1/0 is, but it's important that you keep in mind that you will have to make a new "algebraic" structure to put it in. The only reason you can't divide by zero in your typical number systems (they're called Rings and Fields) is that they simply were not designed with it in mind. You can't divide by zero in fields b/c by I had a thread in Lost Threads on the old board where I developed a system of how to work with 1/0 and powers of 1/0. That doesn't mean it's the only system. Small hacker's definition is built upon a logical deduction based on how you usually expect to handle numbers, but it will break your ring structure if you use it. edit again: btw, does anybody know why the Lost Threads are still restricted on the archive, whereas the staff forums aren't? | ||||||
HyperHacker Posts: 220/5072 |
I see no +. | ||||||
Jagori Posts: 30/155 |
x->0 became x->0+ (approaching 0 from the positive side) | ||||||
Alastor Posts: 663/8204 |
Am I the only one not seeing a difference here?
What was fixed? | ||||||
NSNick Posts: 172/2228 |
Originally posted by Squash MonsterOriginally posted by NSNicklim 1 = Infinity Fixed. | ||||||
Omega45889 Posts: 29/92 |
Welcome to calculus 1... | ||||||
Young Guru Posts: 31/279 |
math is fun. I especially like when you get into vector spaces, because there is no division, only multiplication and addition/subtraction. it makes life simple and kinda explains this. So, you can multiply vector A by the 0 and get a zero vector. Now, if you want to divide A by the zero vector you'd have to multiply A by the inverse of the zero vector. But the zero vector has no inverse so you cannot divide by 0, at least in vector spaces.
That might be kinda off. i've just spent the last 5 hours going through 4 tests and one entire book of linear algebra and a third of a book of O.D.E.s | ||||||
Squash Monster Posts: 62/296 |
Originally posted by NSNicklim 1 = Infinity Nope, not quite. I had that answer at the end of my post and had to edit it because I made the same mistake. The limit of that is infinity if you approach from the positive, or negative infinity if you approach from the negative. So there's no actual value for the normal limit. Which really does a lot to explain why things end up breaking when people try to assign values to 1 / 0. | ||||||
NSNick Posts: 171/2228 |
lim 1 = Infinity |