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11-02-05 12:59 PM
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Acmlm's Board - I2 Archive - Brain Teasers - Math riddle i can't answer... | |
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me99909

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Posted on 08-21-04 08:49 AM Link | Quote
I can't figure this out

Three guys walk into a hotel
The clerk charges them 30 Zenny (yes, zenny)
The guys pay 10z each and go to their room
Later the clerk realizes that he charged them too much
and gives the bellhop 5z to give back to the guys
the bellhop realizes that he can't split 5 evenly, so he keeps 2
and gives the guys 1z each
that means the guys only payed 9z each right?
well, 3 x 9 = 27
and that plus the 2 the bellhop took makes 29
the question is, what happened to the last zenny?

EDIT: ....wait a minute, i think i figured it out, who else can?


(edited by me99909 on 08-20-04 11:53 PM)
Dracoon

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Posted on 08-21-04 08:55 AM Link | Quote
Umm you got to think like this. The total Z is 35 since the whole bellhop thing. 3 that he gave to each of they guys 2 he kept for himself and the 30 they payed. I don't see a problem...
me99909

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Posted on 08-21-04 09:19 AM Link | Quote
The problem:
Quote:
well, 3 x 9 = 27
and that plus the 2 the bellhop took makes 29
the question is, what happened to the last zenny?
End Quote:

the original total was 30
now it is 29
what is wrong with the math?

Originally posted by Dracoon
Umm you got to think like this. The total Z is 35 since the whole bellhop thing. 3 that he gave to each of they guys 2 he kept for himself and the 30 they payed. I don't see a problem...


try rereading it.


(edited by me99909 on 08-21-04 12:20 AM)
Dracoon

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Posted on 08-21-04 09:31 AM Link | Quote
They payed 10 each and got 1 back(each)... the bellhop kept 2 there is no problem. So really you could say they only payed 9 each in the first place and the bellhop just took the two extra.

(10 X 3 - 5) + (2 + 3)

All the money is there you are just forgetting to take the 3 away from the total as it was a return.
me99909

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Posted on 08-21-04 09:35 AM Link | Quote
one problem, the total should be 30, but as your math has it's way, it is 29

Originally posted by Dracoon
They payed 10 each and got 1 back(each)... the bellhop kept 2 there is no problem. So really you could say they only payed 9 each in the first place and the bellhop just took the two extra.



9 each 3 guys
9 * 3 = 27
bellhop took two
27 + 2 = 29
needs to be 30

(putting it simply) this is what you need to solve, what is wrong with the above math?

Edit: I realized something, so my post has completly changed


(edited by me99909 on 08-21-04 12:36 AM)
(edited by me99909 on 08-21-04 12:36 AM)
(edited by me99909 on 08-21-04 12:37 AM)
(edited by me99909 on 08-21-04 12:40 AM)
(edited by me99909 on 08-21-04 12:40 AM)
(edited by me99909 on 08-21-04 12:41 AM)
(edited by me99909 on 08-21-04 12:43 AM)
Dracoon

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Posted on 08-21-04 09:46 AM Link | Quote
Why would it need to be 30 if they got money back changing the entire thing. There was a mistake on the first formula (10 X 3) so the person changed it and the 5 should have gone evenly (about 1.65 or so). In other words the two formulas have no connection. One was an error and the other one is too.
me99909

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Posted on 08-21-04 09:51 AM Link | Quote
Originally posted by Dracoon
Why would it need to be 30 if they got money back changing the entire thing. There was a mistake on the first formula (10 X 3) so the person changed it and the 5 should have gone evenly (about 1.65 or so). In other words the two formulas have no connection. One was an error and the other one is too.


the first formula 10 x 3 is true
they did in fact pay the clerk 30, originally
but that was overchargeing so he sent 5 back
the bellhop kept 2 of 5
the guys payed 9 each in the end
but 3 guys times 9 equals 27
and, adding the two the bellhop took makes 29

the starting money was 30
by this math, it is 29

what is wrong with the math?
you cannot split into fractions
Dracoon

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Posted on 08-21-04 09:54 AM Link | Quote
I dunno what is wrong with your math but if you make me drag it out...

10 X 3= 30
30-5=25
25+3(their refund) + 2 (bellhops money)=30

I am not quite sure why your math is comming to 29, but maybe multiplin isn't the right thing?
me99909

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Posted on 08-21-04 09:57 AM Link | Quote
Originally posted by Dracoon
I
10 X 3= 30
30-5=25
25+3(their refund) + 2 (bellhops money)=30



i mind as well say it, they were charged 27
the bellhops money was included in the 27
the + 2 shouldn't have been done in the first place

Edit: well, that was quick, i need to come up with another math riddle, actually, that riddle came from Megaman bn 4, which got it from somewhere else


(edited by me99909 on 08-21-04 12:59 AM)
(edited by me99909 on 08-21-04 12:59 AM)
Dracoon

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Posted on 08-21-04 10:00 AM Link | Quote
No because if you want to get technical they are still missing 2 dollars because the bellhop took it and it was supposed to be evenly devided between them...
me99909

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Posted on 08-21-04 10:01 AM Link | Quote
Originally posted by Dracoon
No because if you want to get technical they are still missing 2 dollars because the bellhop took it and it was supposed to be evenly devided between them...


but it couldn't be divided evenly, there are no fractions of zenny


(edited by me99909 on 08-21-04 01:02 AM)
Dracoon

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Posted on 08-21-04 10:04 AM Link | Quote
Oh I keep thinking of USA money maybe that is why we see this differently...
me99909

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Posted on 08-21-04 10:11 AM Link | Quote
I live in the USA, zenny is just game money... Ex: BoF, MMbn

EDIT: this sure is a lot of posts in a short time, between two people no less


(edited by me99909 on 08-21-04 01:15 AM)
NSNick
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Posted on 08-21-04 02:16 PM Link | Quote
Originally posted by me99909
this sure is a lot of posts in a short time, between two people no less
Yes it is. Tone it down. Also, shorten your sig, it's unnecessarily long (try taking out the line breaks).

As for your problem, the way you get 29 sounds right, but isn't. The math simply doesn't work the way it's described, which is why you don't come up with 30.
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Posted on 09-12-04 03:11 PM Link | Quote
Originally posted by me99909
the bellhop realizes that he can't split 5 evenly, so he keeps 2
and gives the guys 1z each



Shouldn't he keep 3z?

If he keeps 2z and gives the guys 1z each that makes 4z and he was given 5z.
NSNick
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Posted on 09-12-04 04:00 PM Link | Quote
Whoa, bump.
Teundusia

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Posted on 10-14-04 05:07 PM Link | Quote
OK, I have this exact question in a logic book and here is the answer...

The math u r performing isn't right... They didn't pay 9 each, they should have payed 25 altrogether, but the 3 they got back plus the two in the waiters pocket total 30... in other words

Incorrect: 9x3+2=29
Correct: 25+3+2=30

(Simple Math: They payed 30, but should have payed 25. the 29 comes from the fact that the question misjudges you to think that they paid 9 each, but they have actually spent 30 each, with a 25 offer, plus 2 in the pocket and 3 between the men)

I didn't exactly understand the answer myself but that is exactly what it says in the book


(edited by RYjet911 on 10-16-04 06:29 AM)
FFDude

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Posted on 10-17-04 06:03 PM Link | Quote
Its simple.See,like you said,it makes you think they paid nine each.whereas they ACTUALLY spent 25 altogether.if they spent nine each then the multiplactation and adding would throw the answer off because they DIDNT REALLY SPEND NINE EACH
Instead, the actually spent 9.1/3 each, which adds the missing one.
1/3 X 3 = 1
9 X 3= 27
27 + 1 + 2 = 30
The puzzle makes you think they spent only 9,but they really spent 9 1/3.
Have you gone through algebra yet?Its simple math,and you dont even need to know algebra. You are looking at the puzzle from the wrong angle, which creates a paradox that they really paid an extra 1/3 but not easily figurable. the fact of the matter is that you are making the puzzle too complicating with multiplying. But if you do it backwards
30-5=25
25+3+2=30
And all this came from a twelve yr old oO
Teundusia

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Posted on 10-19-04 11:41 PM Link | Quote
The question itself isn't actually a math question... It's a logical answer question, meaning you have to think around it logically, not just with math
me99909

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Posted on 10-22-04 05:12 AM Link | Quote
Originally posted by RYjet911
The question itself isn't actually a math question... It's a logical answer question, meaning you have to think around it logically, not just with math


This thread should be long gone, but this is pretty much the answer. It is a math riddle, but more of a logic question. If you'd look at me talking to Dracoon, you would have seen me say No Fractions. Sorry, but you are wrong FFDude.
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