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11-02-05 12:59 PM
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Acmlm's Board - I2 Archive - Brain Teasers - Strange Math Riddles | |
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KATW

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Posted on 07-04-04 04:38 AM Link | Quote
x=19.27~
y=5.18~
JJ64

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Posted on 07-04-04 08:53 PM Link | Quote
Yes, Kirby ATW gets the point.

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Question 37 (1 point)-

What is 9 times the square root of 2 to the 16th power?
KATW

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Posted on 07-04-04 10:19 PM Link | Quote
If you mean 9 x |sqrt 20| ^ 16, then 2304
Grey the Stampede

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Posted on 07-05-04 12:25 AM Link | Quote
9 X (sqrt2)^16 = 2304.
(9 X sqrt2)^16 = 4.74 X 10^17.

There are two separate answers here, depending on your order of operations. Since it goes PEMDAS (parentheses first), the answer depends on where the parentheses lie.
JJ64

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Posted on 07-05-04 03:36 AM Link | Quote
Another point for Grey, he had both answers...

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Question 38 (1 point)-

Find the surface area and volume of a sphere with radius 28.
Heian-794

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Posted on 07-05-04 12:37 PM Link | Quote
The volume is 4/3 pi r^3, or (4/3) (pi) (28^3) = 29269 1/3 * pi
(in decimals, approx. 91952.32)

The surface area is 4 pi r^2, or 3136 pi
(in decimals, approx. 9852.03)
JJ64

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Posted on 07-05-04 08:06 PM Link | Quote
It's getting close again...

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Question 39 (1 point)-

Give 5 sets of points on this line:

y=7x+7
NSNick
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Posted on 07-05-04 11:35 PM Link | Quote
(-2,-7)
(-1,0)
(0,7)
(1,14)
(2,21)
JJ64

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Posted on 07-06-04 06:30 AM Link | Quote
And NSNick is now in sole possession of 3rd.

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Question 40 (1 point)-

There are 1300 green footballs, 423472 blue footballs, 5482394652 purple footballs, and 4257834895723 normal footballs. What is the probability of getting a green football (assuming you get one randomly)

You know, that's really an overproduction, if you ask me.
KATW

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Posted on 07-06-04 07:16 AM Link | Quote
Theres enough footballs to give each person on the earth over 10...

.... 4.26 x 10^10 to 13...

PLEASE dont ask me to bring it down any farther
Heian-794

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Posted on 07-06-04 02:26 PM Link | Quote
1300 / (1300 + 423472 + 5482394652 + 4257834895723)

~= 3.053 x10^-10 or 1 in 3,275,679,661

Assuming, or course, that "normal footballs" are brown and do not include green. I seem to recall a college football team years ago wearing uniforms with footballs on the front to disguise who was carrying the ball. The opposing coach thwarted them by using bright red footballs in the game, insisting that there were no regulations on the color of a normal football!

Note that for an approximate answer you can just ignore all but the green and normal footballs, since normal ones are so frequent. This approximation also gives 3.053e-10, but is ever so slightly higher when more decimal places are considered.


(edited by Heian-794 on 07-06-04 05:27 AM)
(edited by Heian-794 on 07-06-04 05:29 AM)
JJ64

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Posted on 07-06-04 09:04 PM Link | Quote
And Heian-794 gets the point, actually.

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Question 41 (1 point)-

Solve these right triangles:

Triangle 1: Sides: 25, 25

Triangle 2: Side: 10, Angle: 30

Triangle 3: Side: 5, Angle: 36
Heian-794

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Posted on 07-06-04 11:57 PM Link | Quote
Triangle 1: sides 25, 25, 35

Triangle 2 (putting the 30-degree angle opposide the 10-unit side): sides 10, 10sqrt 3, 20

Triangle 3: (assuming the side 5 is opposite the 36-deg angle again; solved using the sine and tangent of 36) sides 5, 6.88, 8.503
kornfan
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Posted on 07-09-04 07:44 AM Link | Quote
Can you draw us some examples for the triangles?
Heian-794

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Posted on 07-09-04 11:49 AM Link | Quote
I don't think I could draw these things in ASCII considering that the angles have to be exact. But the lengths of the three sides unequivocally determine the shapes/sizes/angles of the triangles.
JJ64

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Posted on 07-10-04 04:53 AM Link | Quote
Um... for that to be correct, I need angles also.

Solving a right triangle means giving all sides and angles.
Grey the Stampede

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Posted on 07-10-04 07:18 AM Link | Quote
Triangle one: 25,25,25, All angles are 60 degrees.
Triangle two: 10, 10sqrt3, 20, angles are 30, 60, and 90, respectively (as in opposing the side respective to it).
Triangle three: Sides 5, 6.88, 8.503, angles 36, 54, 90, respecitve in the same manner as triangle two.
JJ64

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Posted on 07-11-04 11:49 PM Link | Quote
Grey, it's solve these Right Triangles. Remember that? Number 3 is right, the other two are wrong.
Grey the Stampede

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Posted on 07-12-04 12:17 AM Link | Quote
OK then, Triangle 1 is 25, 25, 35.3553, with angles 45, 45, 90.
Triangle 2's got me stumped. Excuse my lack of attention to the question.
Heian-794

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Posted on 07-12-04 12:48 AM Link | Quote
For Triangle 1, I rounded to the nearest integer when I said
Triangle 1: sides 25, 25, 35
; strictly speaking, it's 25, 25, 35.355, and with two sides equal, of course it's a 45-90-45 right triangle.

Grey's answer (and mine) seem fine for Triangle 2; it's your basic 30-60-90 triangle, in which sides will necessarily be N, 2N, and Nsqrt3.

For triangle 3, the sides are 5, 6.88, 8.503 and the angles are 90, 36, and 54.


(edited by Heian-794 on 07-11-04 03:50 PM)
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