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| Acmlm's Board - I2 Archive - Brain Teasers - Strange Math Riddles |
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JJ64 Boo Level: 45 Posts: 350/919 EXP: 640956 For next: 19208 Since: 05-22-04 From: Green Bay, WI Since last post: 441 days Last activity: 269 days |
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| That's right, it's Strange Math Riddles! The questions will start easy, but get more and more difficult as we go on. I'm your host, Jason, so let's get started! Find the number of Red Octorocks, and subtract the number of Tektites from it. Multiply this by the number of Ninjis, and subtract the number of Silver Battleaxes from it. What is this number? Note: Look at the ranks page on "All Users". |
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Teddylot It was a dark and stormy night ... Level: 44 Posts: 273/851 EXP: 606742 For next: 4543 Since: 03-15-04 From: Not today. Since last post: 1 day Last activity: 8 hours |
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| Teddylot: *pops up from behind the participants' podium* Hi there everybody! I'm Teddylot, a game show host/adventurer, and I've come here to do some mathematically challenging problems. *thumbs up* [(Octorocks - Tektites) Ninjis] - Silver Battleaxes = Answer [(69 - 30) 10] - 3 = 387 And this is as of . . . right now. |
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wolfman2000 Red Paratroopa Level: 21  Posts: 111/161 EXP: 49927 For next: 16 Since: 03-15-04 Since last post: 471 days Last activity: 339 days |
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| Red Octorocks: 69 Tektikes: Umm...color wasn't specified. Guessing both kinds, saying 59. Ninjis: 10 Silver battleaxes: Again, regular or + wasn't specified. Guessing both, 4. 69 - 59 = 10 X 10 = 100 - 4 = 96. |
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JJ64 Boo Level: 45 Posts: 351/919 EXP: 640956 For next: 19208 Since: 05-22-04 From: Green Bay, WI Since last post: 441 days Last activity: 269 days |
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| Teddylot, the MindTrap people are getting sick of waiting. Anyway, wolfman2000 caught the hidden trick, so he gets the point. Scores 1st. wolfman2000-1 point 2nd. Teddylot-0 points Question 2 (1 point): There are 500 people that will go a school next year. 1/5 are staff. 100 will be 5th grade students, 110 will be 4th, 70 will be 3rd, and 90 for 2nd. The rest are 1st. There are 2 first grade classes. About 2/3 of the students in both classes combined will be 5 while entering, the others 6. How many 6-year-olds will there be in kindergarten? (edited by JJ64 on 06-15-04 01:09 PM) (edited by JJ64 on 06-15-04 04:58 PM) |
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Teddylot It was a dark and stormy night ... Level: 44 Posts: 276/851 EXP: 606742 For next: 4543 Since: 03-15-04 From: Not today. Since last post: 1 day Last activity: 8 hours |
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| Teddylot: *eyes JJ## peculiarly* Hello . . . This is a different game show. In MindTrap, I'm still out there trying to fix those stupid computers. I know it's confusing, so don't try and bust your brain cells to try and figure it out. Anyway, the answer: We don't know. No information was given about those stupid Kindie Gardeners. Teddylot: Oh . . . and you're stealing (pretty much) my copyrighted point scale. *points to this game show's screen* Think up your own or pay me a dollar for each time you use it!  . . . You owe me a dollar.  Also, I would protest the last question, but I'm too hungry to. So . . . *goes to get a bite to eat* (edited by Teddylot on 06-15-04 03:24 PM) |
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Heian-794 Red Super Koopa Level: 44 Posts: 111/896 EXP: 611014 For next: 271 Since: 06-01-04 From: Kyoto, Japan Since last post: 21 days Last activity: 10 days |
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| There are zero students in kindergarten, because: There are 500 people that will go a school next year. 1/5 are staff. 100 will be 5th grade students, 110 will be 4th, 70 will be 3rd, and 90 for 2nd. The rest are 1st. Looks like everyone's accounted for right there. No space left for kindergarteners. |
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JJ64 Boo Level: 45 Posts: 375/919 EXP: 640956 For next: 19208 Since: 05-22-04 From: Green Bay, WI Since last post: 441 days Last activity: 269 days |
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| Where do I send the dollar to, Teddylot? Anyway, Heian-794 has it. Scores 1st. wolfman2000-1 point 1st. Heian-794-1 point 3rd. Teddylot-0 points Question 3 (1 point): There are 4 slides at Joanne's Waterpark. One is a kiddie slide, which goes about 1/3 of the speed of the tube slide. The tube slides goes 3/2 the speed of the open slide. The drop slide goes 4 times the speed of the open slide. The other is the open slide. How fast does each slide go? Note: Use what you have to find the speed of the open slide. |
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Emptyeye Real American Level: 67 Posts: 247/2273 EXP: 2488421 For next: 104451 Since: 05-24-04 From: I DUNNOOOOOOOO!! Since last post: 9 hours Last activity: 4 hours |
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| There's not enough information to give exact numbers. There IS enough information to determine ratios. The open slide goes at Speed X The drop slide goes at 4X The kiddie slide goes at 1/2X The tube slide goes at 3/2X |
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JJ64 Boo Level: 45 Posts: 399/919 EXP: 640956 For next: 19208 Since: 05-22-04 From: Green Bay, WI Since last post: 441 days Last activity: 269 days |
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| And another hidden twist is caught, and Emptyeye gets the point. Scores 1st. wolfman2000-1 point 1st. Heian-794-1 point 1st. Emptyeye-1 point 4th. Teddylot-0 points A fairly easy one... for now... Question 4 (1 point): A train leaves point A at 5:00. Another train leaves point B at 7:00. Point C is where the trains will intersect, Point A and B is 200 miles apart. Both trains are moving at 50 MPH. Where is point C, and when will they intersect at point C? (edited by JJ64 on 06-17-04 11:18 AM) |
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wolfman2000 Red Paratroopa Level: 21 Posts: 115/161 EXP: 49927 For next: 16 Since: 03-15-04 Since last post: 471 days Last activity: 339 days |
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| 5:00: A goes 50 "east" let's say. 5:30: A goes another 50 east. 6:00: A goes another 50 east. 6:30: A goes another 50 east. 7:00 A arrives at the station the moment B starts going 50 "west". C is actually point B, and they will meet at 7:00. |
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JJ64 Boo Level: 45 Posts: 402/919 EXP: 640956 For next: 19208 Since: 05-22-04 From: Green Bay, WI Since last post: 441 days Last activity: 269 days |
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| Wow, I missed that. Anyway, wolfman2000 takes the lead. Scores 1st. wolfman2000-2 points 2nd. Heian-794-1 point 2nd. Emptyeye-1 point 4th. Teddylot-0 points Question 5 (1 point)- Assume XY=7, YZ=4, and XZ=5. If triangle XYZ is right, find the area and perimeter of a similar right triangle with a scale factor 1 to 2. |
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KATW King Yoshi "If you stare at something long enough, it can be funny." Level: 86  Posts: 902/3959 EXP: 6087979 For next: 54128 Since: 03-15-04 Since last post: 7 hours Last activity: 5 hours |
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| Mkay... ya got a triangle that is now AB=14 BC=8 and AC=10... Perimeter is 14 + 8 + 10 = 32 Area=1/2bh A=1/2(14)10 A=7x10 A= 70... So perimeter = 32units And Area = 70unitsSqrd |
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wolfman2000 Red Paratroopa Level: 21 Posts: 117/161 EXP: 49927 For next: 16 Since: 03-15-04 Since last post: 471 days Last activity: 339 days |
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| Wait a second... I sense another trick. Pythagoren (spelling) Theorem states that for right triangles, A^2 + B^2 = C^2, where A, B, and C are sides. 4^2 = 16 5^2 = 25 7^2 = 49 16 + 25 != 49 (for non java guys, != means not equal to) This can't be a right triangle under any circumstance. |
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JJ64 Boo Level: 45 Posts: 427/919 EXP: 640956 For next: 19208 Since: 05-22-04 From: Green Bay, WI Since last post: 441 days Last activity: 269 days |
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| Another trick of mine, so wolfman2000 goes farther into the lead. Scores 1st. wolfman2000-3 points 2nd. Heian-794-1 point 2nd. Emptyeye-1 point 4th. Kirby all the way-0 points 4th. Teddylot-0 points Question 6 (1 point): Another right triangle with side lengths 5, 12, and 13 has the same area as a paralellogram. Find the side lengths of the paralellogram. Note: There is more than one possible answer. |
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wolfman2000 Red Paratroopa Level: 21 Posts: 119/161 EXP: 49927 For next: 16 Since: 03-15-04 Since last post: 471 days Last activity: 339 days |
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| Finally, a no trick problem. This is a true right triangle, so .5 * 5 * 12 = 30. Paralellograms can also be rectangles, so we can have a rectangle/paralellogram with sides AB and CD at 6, and BC and DA at 5. A-----B |X X X| D-----C (edited by wolfman2000 on 06-18-04 10:15 AM) (edited by wolfman2000 on 06-18-04 10:15 AM) (edited by wolfman2000 on 06-18-04 10:16 AM) |
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JJ64 Boo Level: 45 Posts: 437/919 EXP: 640956 For next: 19208 Since: 05-22-04 From: Green Bay, WI Since last post: 441 days Last activity: 269 days |
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| And another point for wolfman2000... 1st. wolfman200-4 points 2nd. Heian-794-1 point 2nd. Emptyeye-1 point 4th. Kirby all the way-0 points 4th. Teddylot-0 points Question 7 (1 point)- There was 7 inches of snow due to a recent storm. 2/7 of that snow was shoveled. Another 3 inches fell then. 2/7 of the original amount plus the extra 3 inches of snow was plowed away. Then triple the current amount of snow fell onto the current snow. 1/2 of that was shoveled away. 1/3 of the current amount fell. How much snow is on the ground? |
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KATW King Yoshi "If you stare at something long enough, it can be funny." Level: 86 Posts: 914/3959 EXP: 6087979 For next: 54128 Since: 03-15-04 Since last post: 7 hours Last activity: 5 hours |
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| According to the math... there should be 5 inches of snow on the ground... | |||
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JJ64 Boo Level: 45 Posts: 465/919 EXP: 640956 For next: 19208 Since: 05-22-04 From: Green Bay, WI Since last post: 441 days Last activity: 269 days |
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| How do you get 5 inches? That seems to be wrong. | |||
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NSNick Laidback Admin Level: 85  Posts: 493/3875 EXP: 5895841 For next: 2699 Since: 03-15-04 From: North Side School: OSU Since last post: 9 hours Last activity: 1 hour |
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| But 3 inches sounds about right to me. | |||
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JJ64 Boo Level: 45 Posts: 484/919 EXP: 640956 For next: 19208 Since: 05-22-04 From: Green Bay, WI Since last post: 441 days Last activity: 269 days |
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| No, it's not three either. I'll give out a hint. 1. Start with 7 inches 2. Subtract 2/7 of previous amount (1) 3. Add 3 inches to current amount (2) 4. Subtract 2/7 of the original amount (1) and 3 inches, all to the previous amount (3) 5. Add 3 times the current amount (4) 6. Divide the current amount (5) by 2 7. Add 1/3 to the current amount (6) What is the 7th amount? That's the answer. |
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